4+sqrt(4x^2+3x)=2x

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Solution for 4+sqrt(4x^2+3x)=2x equation:


Simplifying
4 + sqrt(4x2 + 3x) = 2x

Reorder the terms:
4 + qrst(3x + 4x2) = 2x
4 + (3x * qrst + 4x2 * qrst) = 2x
4 + (3qrstx + 4qrstx2) = 2x

Solving
4 + 3qrstx + 4qrstx2 = 2x

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 3qrstx + -4 + 4qrstx2 = -4 + 2x

Reorder the terms:
4 + -4 + 3qrstx + 4qrstx2 = -4 + 2x

Combine like terms: 4 + -4 = 0
0 + 3qrstx + 4qrstx2 = -4 + 2x
3qrstx + 4qrstx2 = -4 + 2x

Reorder the terms:
4 + 3qrstx + 4qrstx2 + -2x = -4 + 2x + 4 + -2x

Reorder the terms:
4 + 3qrstx + 4qrstx2 + -2x = -4 + 4 + 2x + -2x

Combine like terms: -4 + 4 = 0
4 + 3qrstx + 4qrstx2 + -2x = 0 + 2x + -2x
4 + 3qrstx + 4qrstx2 + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
4 + 3qrstx + 4qrstx2 + -2x = 0

The solution to this equation could not be determined.

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